0=4.9x^2-28x+2

Solution for 0=4.9x^2-28x+2 equation:

0=4.9x^2-28x+2

We move all terms to the left:

0-(4.9x^2-28x+2)=0

We add all the numbers together, and all the variables

-(4.9x^2-28x+2)=0

We get rid of parentheses

-4.9x^2+28x-2=0

a = -4.9; b = 28; c = -2;
Δ = b2-4ac
Δ = 282-4·(-4.9)·(-2)
Δ = 744.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-\sqrt{744.8}}{2*-4.9}=\frac{-28-\sqrt{744.8}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+\sqrt{744.8}}{2*-4.9}=\frac{-28+\sqrt{744.8}}{-9.8}
$